5(t^2+2t+5)=0

Solution for 5(t^2+2t+5)=0 equation:

Simplifying
5(t2 + 2t + 5) = 0

Reorder the terms:
5(5 + 2t + t2) = 0
(5 * 5 + 2t * 5 + t2 * 5) = 0
(25 + 10t + 5t2) = 0

Solving
25 + 10t + 5t2 = 0

Solving for variable 't'.

Factor out the Greatest Common Factor (GCF), '5'.
5(5 + 2t + t2) = 0

Ignore the factor 5.
Subproblem 1
Set the factor '(5 + 2t + t2)' equal to zero and attempt to solve:

Simplifying
5 + 2t + t2 = 0

Solving
5 + 2t + t2 = 0

Begin completing the square.

Move the constant term to the right:

Add '-5' to each side of the equation.
5 + 2t + -5 + t2 = 0 + -5

Reorder the terms:
5 + -5 + 2t + t2 = 0 + -5

Combine like terms: 5 + -5 = 0
0 + 2t + t2 = 0 + -5
2t + t2 = 0 + -5

Combine like terms: 0 + -5 = -5
2t + t2 = -5

The t term is 2t.  Take half its coefficient (1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
2t + 1 + t2 = -5 + 1

Reorder the terms:
1 + 2t + t2 = -5 + 1

Combine like terms: -5 + 1 = -4
1 + 2t + t2 = -4

Factor a perfect square on the left side:
(t + 1)(t + 1) = -4

Can't calculate square root of the right side.

The solution to this equation could not be determined.

This subproblem is being ignored because a solution could not be determined.

The solution to this equation could not be determined.